121x^2+37=38

Solution for 121x^2+37=38 equation:

121x^2+37=38

We move all terms to the left:

121x^2+37-(38)=0

We add all the numbers together, and all the variables

121x^2-1=0

a = 121; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·121·(-1)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-22}{2*121}=\frac{-22}{242}
=-1/11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+22}{2*121}=\frac{22}{242}
=1/11
$